Subject: Re: [xsl] Default Rendering of HTML? From: Shawn <sgrover@xxxxxxxxxxxxxx> Date: Sun, 21 Nov 2004 13:42:46 -0700 |
I've have partial success now. I tried two methods. First I tried the <xsl:output> like so: <xsl:output method="html" version="4.0" omit-xml-declaration="yes" cdata-section-elements="text" indent="yes" /> This didn't really make any difference. Then while researching how to handle HTML tags in XML, I came across a reference that used xsl:copy-of, instead of value-of. It occurred to me that what I was trying to do was place the entire node into my output, so copy-of was what I should be using. So, I changed the <xsl:value-of select="text"/> line of my XSL to read <xsl:copy-of select="text"/> - and suddenly my HTML began to work. I had two nodes that were to get rendered, but the first (which didn't contain HTML tags) didn't. I resolved this by removing the <xsl:output> tag I had tried earlier. So, I have a working solution. But, I'm not sure if this is going to be suitable in all cases with HTML tags embedded in XML, or if there is a better way of doing this. Any suggestions are appreciated. Shawn On Sunday 21 November 2004 13:13, Shawn wrote: > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > <xsl:template match="/news"> > <xsl:apply-templates/> > </xsl:template> > > <xsl:template match="item"> > <p> > <span> > <xsl:attribute name="class">newsDate</xsl:attribute> > <xsl:value-of select="date"/> > </span> > <br/> > <span> > <xsl:attribute name="class">newsTitle</xsl:attribute> > <xsl:value-of select="title"/> > </span> > <br/> > > <xsl:value-of select="text"/> > </p> > </xsl:template> > </xsl:stylesheet>
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