Subject: RE: [xsl] document() path relative to current document From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Tue, 23 Nov 2004 18:17:55 -0000 |
> <xsl:variable name="path" select="concat(?PATHINFOMISSING?, > @href)"/> > <xsl:variable name="external-doc" select="document($path)"/> > > Is there a way to get ?PATHINFOMISSING? / the path of the transformed > document? In XPath 2.0 you can get the base URI of a node using the base-uri() function. Note that the way to combine a base URI with a relative URI is not using concat(), but using the resolve-uri() function - the algorithm is in RFC 2396, and is only the same as concatenation in a few special cases. Michael Kay http://www.saxonica.com/
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