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Subject: Re: [xsl] Setting variable based on passed in parameter From: que Li <queincanada@xxxxxxxx> Date: Tue, 30 Nov 2004 11:29:29 -0500 (EST) |
Hi Matthew:
I think <xsl:value-of
>
select="/one/two[three/four[contains(text(),$nodeValue)]]"/>
will display the value on the out .It is not to set
the variable value. you need set the variable value on
the same line which you define variable
example:
<xsl:variable name="myvariable" value=""/>
on the xslt, you can't change variable since you
define it. so It is impossible for you to set the
variable value twice.
what you can do:
<xsl:param name="nodeValue">something</xsl:param>
<xsl:param name="valueSearch">false</xsl:param>
<xsl:choose>
<xsl:when test="$valueSearch='false'">
<xsl:variable name="initialResult"
select="/one/two[three/four[contains(text(),$nodeValue)]]"/>
</xsl:when>
<xsl:otherwise>
<xsl:variable name="initialResult"
select="/one/two[three/four[contains(text(),$nodeValue)]]"/>
</xsl:otherwise>
</xsl:choose>
> <xsl:template match="/">
> <xsl:apply-templates select="$initialResult"/>
> </xsl:template>
--- Matthew Hailstone <mhailstone@xxxxxxxxxx> wrote:
> I'm trying to assign a variable a node-set that
> depends on a parameter
> passed into the stylesheet.
>
> <xsl:param name="nodeValue">something</xsl:param>
> <xsl:param name="valueSearch">false</xsl:param>
> <xsl:variable name="initialResult">
> <xsl:choose>
> <xsl:when test="$valueSearch='false'">
> <xsl:value-of
>
select="/one/two[three/four[contains(text(),$nodeValue)]]"/>
> </xsl:when>
> <xsl:otherwise>
> <xsl:value-of
>
select="/one/two[three/four[contains(text(),$nodeValue)]]"/>
> </xsl:otherwise>
> </xsl:choose>
> </xsl:variable>
> <xsl:template match="/">
> <xsl:apply-templates select="$initialResult"/>
> </xsl:template>
> <xsl:template match="/one/two">
> ...
> </xsl:template>
>
>
> I get an error in oXygen saying, "Cannot process a
> result tree fragment
> as a node-set under XSLT 1.0"
>
> Am I doing something wrong?
>
> Thanks in advance. :)
>
> Matthew
>
>
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