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Subject: Re: [xsl] Add attributes Processed File From: "contest.vix" <contest.vix@xxxxxxxxxx> Date: Tue, 7 Dec 2004 09:53:33 -0200 |
Hi,
Thanks for your help.
What I'm trying to do is to group all elements "a" with attribute flag="true"
at the same level at the xml tree that has only one elemnt "b" with attribute
flag="true" among them.
In the example below I marked the group I'm trying to group.
<root>
<a flag="false">
<b flag="false"/>
</a>
<c>
<b flag="false"/>
<a flag="true"/> <--------------
<b flag="true"/> <--------------
<a flag="true"/> <--------------
<a flag="true"/> <--------------
<a flag="true"/> <--------------
</b>
</c>
</root>
the output, should be:
<root>
<a flag="false">
<b flag="false"/>
</a>
<c>
<b flag="false"/>
<group> <-------------- begin new element
<a flag="true"/> <---------- selected group
<b flag="true"/> <---------- selected group
<a flag="true"/> <---------- selected group
<a flag="true"/> <---------- selected group
<a flag="true"/> <---------- selected group
</group> <-------------- end new element
</b>
</c>
</root>
Thanks a lot,
Roger.
>
> > The only solution that i think is to mark te already processed elements
"a".
>
> that clearly isn't a solution as XSLT can not write to teh input, and
> all templaes are side effect free.
>
> Unfortunately I can't follow your problem description well enough to
> suggest any code.
>
> > So I must group all groups of elements "a" that has one element "b" among
them.
>
> what do you mean by "group" here, and in particular what do you mean by
> group of groups.
>
> As your input and output had lots of I couldn't tell which
> elements in the input was being mapped to which element in the output.
>
>
> > I must group all elements "a" with attribute flag="true" follwed by a
> > element "b" with attribute flag="true"
>
> to select all such a elements you would use
>
> select=".//a[@flag='true'][following-sibling::b[@flag='true]]"
>
> but I can't relate that to your sample output. (The above would just
> select one element in your sample input:
>
>
>
>
>
>
>
>
> <<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<
>
>
>
>
>
>
>
>
> David
>
>
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