Re: [xsl] xsl template parameter passing

[Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>]

Samuel,

You are almost there ... you only need to use xsl:copy-of instead of 
xsl:value-of in your named template.

Then the result-tree-fragment you are passing in as a parameter will be 
copied out. xsl:value-of copies only strings, not subtrees.

Cheers,
Wendell

At 07:22 PM 12/8/2004, you wrote:
> I was wondering if anyone has done something similar
> to what I need done.
>
> I have to show users an error whenever something goes
> wrong. I have a template such as this:
>
> <xsl:template name="errorbox">
> <xsl:param name="message" select="''" />
> <div class="errorbox">
> <h2><xsl:value-of
> select="$lang.NBoxError"/>:<xsl:text> </xsl:text></h2>
> <div class="boxcontent">
> <xsl:value-of select="$message"/>

... say <xsl:copy-of select="$message"/> here ...

> </div>
> </div>
> </xsl:template>
>
> this works fine if "$message" is only text. however,
> many times, a link needs to be included in the
> "message" portion. so i dont know how to call a
> template, and pass in the "body" of the message, which
> can contain html. and use xsl to generate that html.
> I've tried something like this, but does not work:
>
> <xsl:call-template name="errorbox" >
> <xsl:with-param name="message" >
> <a>
> <xsl:attribute name="href">URLTEXT</xsl:attribute>
> Link
> </a>
> </xsl:with-param>
> </xsl:call-template>
>
> please help.


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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc.                http://www.mulberrytech.com
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Suite 207                                          Phone: 301/315-9631
Rockville, MD  20850                                 Fax: 301/315-8285
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