Re: [xsl] <xsl:number> in XPath

[António Mota <xptm@xxxxxxx>]

My webmail is not very reliable, sorry for that.

> There is always a current node in XSLT, you can always use an axis in a
> select expression.  so I don't understand this comment.

Yes, there is a current node, but it's the root one, not the one i want the
ancestors at the moment of the select.

<xsl:template match="/">
        <xsl:apply-templates select="/menus/menu | (//menu)[$pos]" />
</xsl:template>

I want both the /menus/menu, the (//menu)[$pos] and their ancestors and first
children, but i can't do something like

<xsl:apply-templates select="/menus/menu | (//menu)[$pos]" |
(//menu)[$pos]/menu
 | ancestor:menu[(//menu)[$pos]]/>

or is there something similar?

> That does seem to be a direct translation of your English into Xpath, so
> presumably this is what you want.

There was no XSL expressions after that, maybe you forget it?

> why do you need to start walking back up the tree here. That select
> selects all ancestor menus that have a parent menu (but not ancestor
> menus that don't have a parent menu), the current node and any menu
> children of the current node.

All this taking as reference the current node, correct? If yes, i think it's
that what i want.

<menu>
<menu>
    <menu>  *
        <menu>  --> this is the (//menu)[$pos]
<menu>

So in the first select i didn't select the one i marked (*), so i need the
ancesters of the (//menu)[$pos]

> sorry, as a matter of policy never check off-list examples (I waste
> enough time just looking at small inlined examples on the list:-)

Puting in words, i have that nested <menu> nodes that i want to expand when i
click then. So at first i want to show all the first-level menus, and when i
click one of then i want to expand to it's first chidrens and so on.

Once agains, thank for your insights.


Citando David Carlisle <davidc@xxxxxxxxx>:


Citando David Carlisle <davidc@xxxxxxxxx>:

>
> (your message came out one word per line, I had to reflow it to read it)
>
>
> Just a comment on,
>
>
> > To my understanding i canot use
> > the axis in the select xpath because they rely on a context node, wich
> > i don't have at the time.
>
> There is always a current node in XSLT, you can always use an axis in a
> select expression.  so I don't understand this comment.
>
> However
>
> > I want to process all <xxx> nodes that
> > are at the 1st level of deepness, plus the <xxx> at absolute position
> > number n
>
> > So i translate this to
> >
> > <xsl:apply-templates
> > select="/menus/menu | (//menu)[$pos]" />
>
> That does seem to be a direct translation of your English into Xpath, so
> presumably this is what you want.
>
> But this looks a bit strange:
>
> > <xsl:for-each
> > select="ancestor::menu/menu | self::menu | menu">
>
> Given that you already slected all your top level menus and the $pos'th
> menu in your first <xsl:apply-templates select="/menus/menu |
(//menu)[$pos]"
> />
> why do you need to start walking back up the tree here. That select
> selects all ancestor menus that have a parent menu (but not ancestor
> menus that don't have a parent menu), the current node and any menu
> children of the current node.
>
> If thats what you want, this is the right thing, but it looks strange to
> me.
>
>
> > The
> > XML:
> > http://gti.clientes.gtinformatica.pt/Site/Java/Menus.xml
>
> sorry, as a matter of policy never check off-list examples (I waste
> enough time just looking at small inlined examples on the list:-)
>
> David
>
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