Subject: Re: [xsl] Xsl copy nodes From: Geert Josten <Geert.Josten@xxxxxxxxxxx> Date: Fri, 17 Dec 2004 07:01:53 +0100 |
<xsl:template match"@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xls:copy> </xsl:template>
Hi, I'm new to xsl. I have the following xml <CLUSTERLIST> <CLUSTER> <STORY ID="1"> <CLUSTER> <STORY ID="2"> </CLUSTER> </CLUSTER> <STORYLIST> <STORY ID="1" ATT1="att1" ATT2="att2"/> <STORY ID="2" ATT1="att1" ATT2="att2"/> </STORYLIST> </CLUSTERLIST>
The output I want is <CLUSTERLIST> <CLUSTER> <STORY ID="1" ATT1="att1" ATT2="att2"/> <CLUSTER> <STORY ID="2" ATT1="att1" ATT2="att2"/> </CLUSTER> </CLUSTER> </CLUSTERLIST>
So I just want to move the story nodes from the story list to the
corresponding positions (by matching the ids) under cluster nodes
Thanks in advance, Ravi.
-- Geert.Josten@xxxxxxxxxxx IT-consultant at Daidalos BV, Zoetermeer (NL)
http://www.daidalos.nl/ tel:+31-(0)79-3316961 fax:+31-(0)79-3316464
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