Subject: [xsl] Continuous path of elements satisfying a condition From: <cgp@xxxxxxxxxxx> Date: Sat, 18 Dec 2004 12:37:59 -0500 |
I have input like this: <root> <item id="1"> <item id="2"> <item id="3"/> <item/> </item> <item> <item/> </item> <item id="4"/> </item> <item> <item/> </item> </root> I am only interested in item elements that have id attributes and form a continuous chain from the child of the root element to a leaf. 1) I can select the leaves and then all the relevant items with <xsl:variable name="leaves" select="//item[@id and not(*) and not (ancestor::item[not(@id)])]"/> <xsl:variable name="items" select="$leaves | $leaves/ancestor::item"/> Is there a better way? 2) In the template for an item, I need to loop through the item's children that meet the conditions (i.e., that are in $items). I've tried this <xsl:variable name="nitems" select="count($items)"/> <xsl:template match="/"> <xsl:apply-templates select="$items"/> </xsl:template> <xsl:template match="item"> <xsl:for-each select="item[count(. | $items) = $nitems]"> ... </xsl:text> </xsl:for-each> </xsl:template> This is fairly elegant but testing in my environment (MSXML) shows it to take 4 seconds while a recursive template that just sums the number of included items that are children of the current item runs about 50 lines but takes half the time to run. Thanks, Chris
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