Subject: RE: [xsl] xsl:sort not working under unix??? From: "Jim Neff" <jneff@xxxxxxxxxxxxxxx> Date: Mon, 20 Dec 2004 13:26:50 -0500 |
> <xsl:sort select="name" data-type="number"/> ^^^^^^ Should that be number? --Jim -----Original Message----- From: Sylvia Murphy [mailto:murphys@xxxxxxxx] Sent: Monday, December 20, 2004 1:23 PM To: xsl mailing list Subject: [xsl] xsl:sort not working under unix??? to demonstrate this behavior, I have created a simple test case. Are there known unix issues or is the stupid newbie error. note the transformation is occuring in the browser (NN7). Thanks, sylvia simple xml file: <?xml version="1.0"?> <?xml-stylesheet type="text/xml" href="./sort.xsl"?> <addressbook> <address> <name>Sylvia</name> <age>39</age> <state>CA</state> </address> <address> <name>Mariana</name> <age>90</age> <state>CO</state> </address> </addressbook> here is the style sheet: <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <html> <head></head> <body> <h1> TEST of SORT</h1> <xsl:for-each select="addressbook"> <xsl:sort select="name" data-type="number"/> <xsl:apply-templates/> </xsl:for-each> </body> </html> </xsl:template> <xsl:template match="address"> <p> <xsl:value-of select="age"/> <xsl:text> </xsl:text> <xsl:value-of select="name"/> <xsl:value-of select="$newline"/> </p> </xsl:template> </xsl:stylesheet>
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