Subject: Re: [xsl] Translating roman numerals into integers with XSLT 2.0 From: Mukul Gandhi <mukul_gandhi@xxxxxxxxx> Date: Mon, 20 Dec 2004 19:50:47 -0800 (PST) |
Following is an improved algorithm.. It will work for any large number.. <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:num="http://whatever" version="2.0" > <xsl:output method="text"/> <xsl:template match="/"> <xsl:call-template name="RomanToInteger"> <xsl:with-param name="roman_number" select="'XXI'" /> <xsl:with-param name="index" select="1" /> </xsl:call-template> </xsl:template> <xsl:template name="RomanToInteger"> <xsl:param name="roman_number" /> <xsl:param name="index" /> <xsl:choose> <xsl:when test="num:toRoman($index) = $roman_number"> <xsl:value-of select="$index" /> </xsl:when> <xsl:otherwise> <xsl:call-template name="RomanToInteger"> <xsl:with-param name="roman_number" select="$roman_number" /> <xsl:with-param name="index" select="$index + 1" /> </xsl:call-template> </xsl:otherwise> </xsl:choose> </xsl:template> <xsl:function name="num:toRoman" as="xs:string"> <xsl:param name="value" as="xs:integer"/> <xsl:number value="$value" format="I"/> </xsl:function> </xsl:stylesheet> Regards, Mukul --- Mukul Gandhi <mukul_gandhi@xxxxxxxxx> wrote: > You could try something like this - > > <?xml version="1.0" encoding="UTF-8"?> > <xsl:stylesheet > xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > > > xmlns:xs="http://www.w3.org/2001/XMLSchema" > > xmlns:num="http://whatever" version="2.0" > > > <xsl:output method="text"/> > > <xsl:variable name="max" select="10000" /> > > <xsl:template match="/"> > <xsl:call-template name="RomanToInteger"> > <xsl:with-param name="roman_number" > select="'XXI'" > /> > </xsl:call-template> > </xsl:template> > > <xsl:template name="RomanToInteger"> > <xsl:param name="roman_number" /> > <xsl:for-each select="1 to $max"> > <xsl:if test="num:toRoman(.) = $roman_number"> > <xsl:value-of select="." /> > </xsl:if> > </xsl:for-each> > </xsl:template> > > <xsl:function name="num:toRoman" as="xs:string"> > <xsl:param name="value" as="xs:integer"/> > <xsl:number value="$value" format="I"/> > </xsl:function> > > </xsl:stylesheet> > > The above XSL assumes, that there is some maximum > value of the number(in this example 10000). > > I see this as an area of improvement.. > > Is there a way to break from xsl:for-each loop when > some condition is met? > here , xsl:if test="num:toRoman(.) = $roman_number" > > Regards, > Mukul > > --- Huditsch Roman <Roman.Huditsch@xxxxxxxxxxxxx> > wrote: > > > Hi again, > > > > Sorry, for bothering you a second time today, > > but I was wondering if there is a more or less > > simple way > > of translating roman numerals into intergers with > > XSLT 2.0. > > > > Or do I have to use the standard method for doing > > this > > describes in the "XSLT Cookbook" by Sal Mangano? > > > > Would be nice if format-number() or anything > similar > > would allow > > me to o this... > > > > Thank you very much for your patience. > > > > wbr, > > Roman > > > > _______________________________________ > > > > Roman Huditsch > > IT and Electronic Publishing > > LexisNexis ARD Orac > > Marxergasse 25 > > 1030 Vienna > > Austria > > ph: +43-1-534 52-1514 > > f: +43-1-534 52-140 > > e-mail roman.huditsch@xxxxxxxxxxxxx > > www.lexisnexis.at > > > > > > > -----Urspr|ngliche Nachricht----- > > > Von: Michael Kay [mailto:mike@xxxxxxxxxxxx] > > > Gesendet: Montag, 20. Dezember 2004 15:20 > > > An: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > > > Betreff: RE: [xsl] Omitting default namespace in > > the output - XSLT 2.0 > > > > > > If you copy elements using xsl:copy-of, the > output > > elements > > > will have the same names as the input elements, > > and the > > > system will automatically add declarations of > the > > namespaces > > > used in these names. You want your output > elements > > to have a > > > different name from the input elements (same > local > > name, > > > different URI). So you can't use copy-of. > > > > > > To copy a tree while renaming elements, use a > > modified form > > > of the identity template rule: > > > > > > <xsl:template match="*"> > > > <xsl:element name="{local-name()}"> > > > <xsl:copy-of select="@*"/> > > > <xsl:apply-templates/> > > > </xsl:element> > > > </xsl:template> > > > > > > Michael Kay > > > http://www.saxonica.com/ > > > > > > > > > > -----Original Message----- > > > > From: Huditsch Roman > > [mailto:Roman.Huditsch@xxxxxxxxxxxxx] > > > > Sent: 20 December 2004 13:52 > > > > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > > > > Subject: [xsl] Omitting default namespace in > the > > output - XSLT 2.0 > > > > > > > > Hi, > > > > > > > > Given an example input like: > > > > > > > > <?xml version="1.0" encoding="UTF-8"?> <norm > > > > xmlns="myDefaultNamespace"> > > > > <table> > > > > <row> > > > > <cell>My Table</cell> > > > > </row> > > > > </table> > > > > </norm> > > > > > > > > I searched for an easy way to get output data, > > which is not > > > associated > > > > to my default namespace any more, with the > help > > of <xsl:copy-of> in > > > > XSLT 2.0 I hoped that the attribute > > "copy-namespaces" set to "no" > > > > would help me here, but unfortunately I had no > > luck with Saxon 8.1.1 > > > > > > > > My output still looks like > > > > > > > > <table> > > > > <row xmlns="myDefaultNamespace"> > > > > <cell>My Table</cell> > > > > </row> > > > > </table> > > > > > > > > > > > > XSLT: > > > > ===== > > > > > > > > <xsl:template match="ln:table"> > > > > <table> > > > > <xsl:copy-of select="node() | @*" > > > > copy-namespaces="no"/> > > > > </table> > > > > </xsl:template> > > > > > > > > > > > > Thanks in advance for your input! > > > > > > > > wbr, > > > > Roman > > > > _______________________________________ > > > > > > > > Roman Huditsch > > > > IT and Electronic Publishing > > > > LexisNexis ARD Orac > > > > Marxergasse 25 > > > > 1030 Vienna > > > > Austria > > > > ph: +43-1-534 52-1514 > > > > f: +43-1-534 52-140 > > > > e-mail roman.huditsch@xxxxxxxxxxxxx > > > > www.lexisnexis.at __________________________________ Do you Yahoo!? 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