Re: [xsl] super basic xsl question

[Jeb Boniakowski <jeb@xxxxxxxxxxx>]

Thanks a lot, that's what I was looking for.

jeb..

On Jan 13, 2005, at 12:09 PM, JBryant@xxxxxxxxx wrote:

> Don't have time for a long reply, but try xsl:copy-of
>
> Jay Bryant
> Bryant Communication Services
> (on contract at Synergistic Solution Technologies)
>
>
>
>
> Jeb Boniakowski <jeb@xxxxxxxxxxx>
> 01/13/2005 10:58 AM
> Please respond to
> xsl-list@xxxxxxxxxxxxxxxxxxxxxx
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> Subject
> [xsl] super basic xsl question
>
>
>
>
>
>
> Thanks to everyone on the list that helped me with my last problem.  I
> still have some fundamental misunderstanding of how xsl is supposed to
> work, because I can't figure out how to do this:
>
> <xmlroot>
>   <child>some text</child>
>   <child><a href="">a link</child>
> </xmlroot>
>
> and convert it to say...
>
> <ul>
>   <li>some text</li>
>   <li><a href="">a link</child>
> </ul>
>
> I've tried various combos like:
> <xsl:template match="child">
>                  <xsl:value-of select="."/>
> </xsl:template>
>
> but that means I lose the <a> tags.
>
> I thought something with <xsl:copy> would work, but that gives me the
> context node, and furthermore, it doesn't give me the children, so it
> does the opposite.  Then I thought fiddling with the 'select' expr in
> the value-of tag would do it, but I can't figure out if there's a
> magical combination of XPath slang that means, "whatever the hell is
> below here, be it tags or text, i want them".
>
> jeb.