RE: [xsl] Line feeds to breaks

[Aaron Johnson <Aaron2.Johnson@xxxxxxxxx>]

Hi Jarno...

<Address>
<objectUrn>2182110</objectUrn>
<addr>10 GLASHIEBURN AVENUE BRIDGE OF DON ABERDEEN</addr>
<postCode>AB22 8UQ</postCode>
<startDay>19</startDay>
<startMonth>1</startMonth>
<startYear>2005</startYear>
<endDay/>
<endMonth/>
<endYear/>
<type>TERM - PARENT</type>
<telNo/>
<timeFrame>present</timeFrame>
</Address>

The breaks need to go into the <addr> node to put the parts on different
lines. I tried &#xA; but it did not work...thanks for your input.

AMJ

......................................................................

Aaron Johnson
GUI / XSLT development
Academic Technologies Group [ATG]
University of the West of England
ext: 81051
t: 0117 3281051
www: http://atg.uwe.ac.uk/aaron
e: aaron2.johnson@xxxxxxxxx

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-----Original Message-----
From: Jarno.Elovirta@xxxxxxxxx [mailto:Jarno.Elovirta@xxxxxxxxx]
Sent: 19 January 2005 11:03
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: [xsl] Line feeds to breaks

Hi,

> Appologies if you have already received this ...our email
> system is playing
> silly buggers...
>
>
>
> I'm having a problem with converting line feeds to html breaks.
>
>
>
> Microsoft value is &#10;
>
>
>
>
> Java /Unix value is &#13;
>
>
>
>
>
> When the page is transformed, the line breaks are huge depending on
> which
> value is used and what platform you display the page on.

In character data, all line breaks are normalized to #xA
<http://localhost/TR/rec-xml/#sec-line-ends>, and the XPath source tree
will only contain #xA characters for line breaks. However, if you use
character references instead, they're left as is. What does your source
look like?

Cheers,

Jarno


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