Subject: Re: [xsl] How can I conditionaly assign a node-set to my variable? From: Dimitre Novatchev <dnovatchev@xxxxxxxxx> Date: Thu, 20 Jan 2005 06:27:09 +1100 |
Use: channel[6 > id or id='P'] [6 > $n and $hasP] | channel[6 > id] [not(6 > $n and $hasP)] Of course, in XPath 2.0 one can simply use a conditional expression: if(expression) then expression else expression Cheers, Dimitre Novatchev. On Thu, 20 Jan 2005 04:13:25 +1000, r.moe@xxxxxxxxxxxxxxxxxx <r.moe@xxxxxxxxxxxxxxxxxx> wrote: > How can I conditionaly assign a node-set to my variable? > Variable needs to have local scope. > Obviously I can't use <xsl:value-of.../>. > I get the error message: > "Reference to variable or parameter 'firstTableRows' must > evaluate to a node list." > > Code: > > <xsl:variable name="firstTableRows"> > <xsl:choose> > <xsl:when test="6>$n and $hasP"> > <xsl:value-of select="channel[6>id or id='P']"/> > </xsl:when> > <xsl:when test="6>$n"> > <xsl:value-of select="channel[6>id]"/> > </xsl:when> > <xsl:otherwise> > <xsl:value-of select="channel[6>id]"/> > </xsl:otherwise> > </xsl:choose> > </xsl:variable> > > Thanks, > Roy
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