Re: [xsl] How to return a result for just the first group

["Juergen" <xsl@xxxxxxxxxxxxxxx>]

Hi Kevin,

> What I want to do is generate text by concatenating the title and
> subtitle of the first language:

<snip>

> <title_list>
> <title type="TITLE" language="de">Gummi- und Kunststoffschlaeuche 
> und -schlauchleitungen mit Drahteinlage; Hydraulik-Impulspruefung mit 
> wechselnder Biegung (ISO 6802:1991)</title>
> <title type="TITLE" language="en">Rubber and plastics hose and hose 
> assemblies with wire reinforcements; hydraulic impulse test with flexing 
> (ISO 6802:1991)</title></title>
> <title type="SUBTITLE" language="en">german version EN 26802:1993</title>
> </title_list>
> <title type="SUBTITLE" language="de">Deutsche Fassung EN 
> 26802:1993</title>

Select the language in a variable first entry or fix with 'de'.
<xsl:variable name="language" select="titlelist/title[1]/@language"/>

Then concat, condition language added, that's all.
<xsl:value-of select="concat(title_list/title[@type='TITLE' and 
@language=$language],
                            $separator,
                            title_list/title[@type='SUBTITLE' and 
@language=$language])"/>

Cheers,

Juergen