Subject: RE: [xsl] Removing line-feeds on a imported tree via document From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Tue, 25 Jan 2005 23:22:49 -0000 |
The xsl:copy-of instruction is only useful where you want to do an exact copy. The standard way to do a transformation where the output is nearly the same as the input is to start with the identity template rule: <xsl:template match="*"> <xsl:copy> <xsl:copy-of select="*"/> <xsl:apply-templates/> </xsl:copy> </xsl:template> and then override it for elements that need to be modified: <xsl:template match="MenuData"> <xsl:copy> <xsl:value-of select="normalize-space(.)"/> </xsl:copy> </xsl:template> Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Antsnio Mota [mailto:amsmota@xxxxxxxxx] > Sent: 25 January 2005 19:12 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Removing line-feeds on a imported tree via document > > Here's another interesting one. In my XSLT i have at some point > > <xsl:copy-of select="$xmldoc/Menus/Menu" /> > > working ok, EXCEPT sometimes i get things like > > <Menu> > <Menu_K>X00066</Menu_K> > <Titulo>(Cada Utente)</Titulo> > <MenuData>SELECT Utente_K, NomeLogin > FROM Utente > WHERE UtenteTipo='U'</MenuData> > <MenuTipo>TXT</MenuTipo> > </Menu> > > Notice the line breaks on MenuData, that is causing me problems later > on. So i want to get rid of then. I've tryed using > > <xsl:copy-of select="normalize-space($xmldoc/Menus/Menu)" /> > > because i don't understand nothing of this, but soon realise the > error, so i went back and define a template > > <xsl:template match="MenuData"> > <xsl:copy><xsl:value-of > select="normalize-space(.)"/></xsl:copy> > </xsl:template> > > but did no good, cause it seems that only match the original MenuDatas > and not the imported ones. > > Any sugestions? Thanks.
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