Re: [xsl] position()

Subject: Re: [xsl] position()
From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>
Date: Wed, 02 Feb 2005 17:59:03 -0500

At 04:52 PM 2/2/2005, you wrote:
        <component name="foo"/>
          <component name="foo"/>
          <target name="foo"/>

Given this XSLT:

      <xsl:template match="/document//target">
          select="ancestor::bundle/component[@name = current()/@name]"/>

How do I select just the first ancestor component?

Will this work?

ancestor::bundle/component[@name = current()/@name and position() = 1]

    Or does that refer to the position of component as a child of
    bundle, therefore matching both components.

The latter.

You can get what you want by grouping all the components and then filtering from the group, instead of filtering only on the XPath step:

(ancestor::bundle/component[@name = current()/@name])[1]

By "first" I assume you mean "first in document order".


====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================

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