Re: [xsl] position()

[Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>]

Alan,

At 04:52 PM 2/2/2005, you wrote:
>    <document>
>       <bundle>
>         <component name="foo"/>
>         <bundle>
>           <component name="foo"/>
>           <target name="foo"/>
>         </bundle>
>       </bundle>
>     </document>
>
>     Given this XSLT:
>
>       <xsl:template match="/document//target">
>         <xsl:apply-tempaltes
>           select="ancestor::bundle/component[@name = current()/@name]"/>
>       </xsl:template>
>
>     How do I select just the first ancestor component?
>
>     Will this work?
>
>       ancestor::bundle/component[@name = current()/@name and position() = 1]
>
>     Or does that refer to the position of component as a child of
>     bundle, therefore matching both components.

The latter.

You can get what you want by grouping all the components and then filtering 
from the group, instead of filtering only on the XPath step:

(ancestor::bundle/component[@name = current()/@name])[1]

By "first" I assume you mean "first in document order".

Cheers,
Wendell


======================================================================
Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc.                http://www.mulberrytech.com
17 West Jefferson Street                    Direct Phone: 301/315-9635
Suite 207                                          Phone: 301/315-9631
Rockville, MD  20850                                 Fax: 301/315-8285
----------------------------------------------------------------------
  Mulberry Technologies: A Consultancy Specializing in SGML and XML
======================================================================