Subject: RE: [xsl] String formatting From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Wed, 2 Feb 2005 23:09:06 -0000 |
If the format is completely predictable, concat(substring(.,1,20), substring(.,24)) - I may have counted wrong. If less predictable, use the replace() function in 2.0 or some combination of substring-after() and substring-before() in 1.0. Alternatively, in 2.0, cast to an xs:dateTime, extract the components using e.g. seconds-from-dateTime(), modify the seconds value, and reconstruct. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Bhaskar, Rajan [mailto:RBhaskar@xxxxxxx] > Sent: 02 February 2005 22:29 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: RE: [xsl] String formatting > > sorry in this form > yyyy-MM-DDThh:mm:ss.SSS-HH:mm but want to translate to > yyyy-MM-DDThh:mm:ss-HH:mm removing the SSS > > > > -----Original Message----- > From: Bhaskar, Rajan [mailto:RBhaskar@xxxxxxx] > Sent: Wednesday, February 02, 2005 5:26 PM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] String formatting > > > > Hi, > I have a string in the form=20 > yyyy-MM-DDThh:mm:ss.SSS-HH:mm but want to translate to=20 > yyyy-MM-DDThh:mm:ss-HH:mm removing the SSS. > > How can i do that. > > thanks, > Rajan
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