Subject: Re: [xsl] Summing grouped elements From: David Carlisle <davidc@xxxxxxxxx> Date: Mon, 7 Feb 2005 13:38:01 GMT |
you haven't shown enough of your stylesheet or any of your input so it's hard to really make any suggestions, but... <xsl:for-each select="$referencias"> what's the definition of $referencias, and what to teh elements in that node set look like? <xsl:if test="generate-id(.)=generate-id($referencias[isbn=$isbn])"> This is just true for the first element with each isbn. <xsl:for-each select="$referencias[isbn=$isbn]"> this selects all the elements with that isbn (probably you ought to be using a key to speed this up) <xsl:sort select="../../../@name" order="ascending" /> <xsl:sort select="../../descricao" order="ascending" /> I assume they work, without seeing your input format it's impossible to say. Total: <xsl:value-of select="sum(../../vagas)" /> <--Here is my problem it doesn't display the total, only appear the value to a single element --> In that case it is most likely ../../vagas only selects one element, but we can't say as we have not seen any input. Make a small (3 or 4 references) input file and a small complete stylesheet and post saying what result you get and what result you want. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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