Subject: RE: [xsl] Select and display a node From: Sébastien Bicaïs <s.bicais@xxxxxxxxxxx> Date: Wed, 9 Feb 2005 17:51:15 +0100 |
Thanx joris for you answer. The problem was actually your 1st solution: I had 2 XML element with the same 'id' attributes... -----Message d'origine----- De : Joris Gillis [mailto:roac@xxxxxxxxxx] Envoyi : mercredi 9 fivrier 2005 10:59 @ : xsl-list@xxxxxxxxxxxxxxxxxxxxxx Objet : Re: [xsl] Select and display a node Tempore 09:57:50, die 02/09/2005 AD, hinc in xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit Sibastien Bicaos <s.bicais@xxxxxxxxxxx>: > <xsl:template match="rss/channel" > > <xsl:for-each select="item/page[@id=456]"> > id = <xsl:value-of select="@id"/> > </xsl:for-each> > </xsl/template> > > But when I run this, I get "id = 456" twice.. > > Any suggestion welcome Hi, I can only see 2 possible explanations: 1) Your real input XML contains elements with the same 'id' attributes. 2) You're not using any tool that displays error messages. You tried this first: <xsl:template match="rss/channel" > <xsl:for-each select="item/page"> id = <xsl:value-of select="@id"/> </xsl:for-each> </xsl:template> Which resulted (correclty) in 2 times "id = ..." And then you changed to: <xsl:template match="rss/channel" > <xsl:for-each select="item/page[@id=456]"> id = <xsl:value-of select="@id"/> </xsl:for-each> </xsl/template> Which is not well-formed xml ('</xsl/template>') and caused the ouput file not to be updated. Thus creating the false impression that it returned 2 times "id = ..." again. regards, -- Joris Gillis (http://www.ticalc.org/cgi-bin/acct-view.cgi?userid=38041) Fiat W3C in tenebris
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