Subject: Re: [xsl] xsl:function, arithmetic From: Mukul Gandhi <mukul_gandhi@xxxxxxxxx> Date: Mon, 14 Feb 2005 10:00:22 -0800 (PST) |
Hi Richard, I am not getting error! The following XSL is working fine.. <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:my="http://whatever" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="text" /> <xsl:template match="/"> <xsl:value-of select="my:increase(3)" /> <xsl:value-of select="my:increase(10.5)" /> </xsl:template> <xsl:function name="my:increase"> <xsl:param name="i" /> <xsl:value-of select="round(1.2 * $i)" /> </xsl:function> </xsl:stylesheet> For argument 3, I am getting output 4; and for argument 10.5, I am getting output 13.. I am using Saxon 8.1.1 . Regards, Mukul --- Richard Lewis <richardlewis@xxxxxxxxxxxxxx> wrote: > Hello, > > I'm having a few problems with an xsl:function. > > Its supposed to take a numerical parameter and > return it multiplied by > 1.2 and rounded: > > <xsl:function name="my:increase"> > <xsl:param name="i" /> > <xsl:value-of select="round(1.2 * $i)" /> > </xsl:function> > > I've tried added an xsl:message to the function to > check the XPath > expression and it seems to be correct, but all the > expressions in my > stylesheet which use this function seem to return > non-numerical results. > I've also tried just returning the parameter > unaltered, in which case I > get no problems. And I've tried things like > 'select="$i + $i div 5"' but > still get the problem. > > I'm using XSLT2, Saxon 8.2B. > > Any ideas? > > Richard __________________________________ Do you Yahoo!? Yahoo! Mail - 250MB free storage. Do more. Manage less. http://info.mail.yahoo.com/mail_250
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