RE: [xsl] RE: Display children of node with given Id!!

["Andrew Welch" <ajwelch@xxxxxxxxxxxxxxx>]

> Following on from my previous post.
> Thanks to those who replied, it is much appreciated.
> This stylesheet matches all nodes that are descended from
> node with a given id.
>
> Two Things:
> 1) How do I modify this stylesheet to include the rendering
> of all top level tree nodes? Can I do this in the
> <xsl:apply-templates select=""/> element. I have tried
> <xsl:apply-templates select="parent::tree or //tree_node[@id
> = $id]"/>???
>
> 2) How do I modify this stylesheet to only display immediate
> children(not grandchildren ect) descended from the node with
> a given id. In the case node id = 7 , nodes 8, 9 will only be
> displayed. Not 10.
>
>
> COMPLETE XML STRUCTURE:
>
> <tree>
>   <tree_node id="7" value="Test">
>     <tree_node id="8" value="Test Sub"/>
>     <tree_node id="9" value="Test Sub One">
>       <tree_node id="10" value="Test Sub Two"/>
>     </tree_node>
>   </tree_node>
>   <tree_node id="11" value="Test 2"/>
> </tree>

For 1) use <xsl:apply-templates select="/tree/tree_node"/> (as I'm
assuming your 'top level tree nodes' are <tree_nodes>?  Maybe you mean
something else?)

For 2) use <xsl:apply-templates select="//tree_node[@id = $id]/tree"
mode="child_only"/> (note the mode) and then add a moded template that
matches <tree_node> but doesn't contain an <xsl:apply-templates/>

cheers
andrew