Subject: Re: [xsl] Newbie question - Muenchian method and XPath From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 22 Feb 2005 22:37:00 GMT |
> So it's dragging all <item>s together (as xsl:key is obviously document wide > and I can't use scope)., which isn't what I want! (I want: I think Jeni has an example (the archives of this list will have lots:-) but basically you just need to make sure that the key has a different value for each different group, so if children of group are to be grouped separately include that in the key <xsl:key name="x" match="item" use="concat(../@value,':',@name)"/> and use a similar concat in the call to key() so your first group is all items which have a key of 1:a for example which should just return apple and banana. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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