Subject: Re: [xsl] Sorting network addresses From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 2 Mar 2005 14:05:20 GMT |
> ....now do u get what i get? no I get: $ saxon ip2.xml ip2.xsl <?xml version="1.0" encoding="UTF-8"?> <networks> <network> <address>1.1.1.1</address> </network> <network> <address>2.3.1.2</address> </network> <network> <address>170.5.2.4</address> </network> </networks> But I just noticed that you are specifying XSLT2 (although you don't have any xslt2 specific features) so I'll try with saxon8: I get same: $ java -jar ../saxon8/saxon8.jar ip2.xml ip2.xsl <?xml version="1.0" encoding="UTF-8"?> <networks> <network> <address>1.1.1.1</address> </network> <network> <address>2.3.1.2</address> </network> <network> <address>170.5.2.4</address> </network> </networks> > To repeat how I did it, > open the XML document, go to the "XSL/XQuery" sorry that would mean downloading xmlspy first which is too much:-) What processor does it use for XSLT2 ? David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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