[xsl] node positioning problem

Subject: [xsl] node positioning problem
From: Spencer Tickner <spencertickner@xxxxxxxxx>
Date: Wed, 30 Mar 2005 10:13:33 -0800
Hi everyone, thanks for the help and all the great responses I've
gleened from ya.

Here we go I got an xml file like so

<!-- AA2 exists -->
<AAA>
    <AAA1></AAA1>
    <AAA2></AAA2>
    <BBB></BBB>
    <CCC></CCC>
    <BBB></BBB> 
</AAA>
<!-- AA2 does not exist -->
<AAA>
    <AAA1></AAA1>
    <BBB></BBB>
    <BBB></BBB>
    <CCC></CCC>
</AAA>

Ok, now in a quick pseudo what I need is

<!-- If AA2 does exist -->
<h4>AAA1 AAA2</h4>
<h6>BBB</h6>
<h6>BBB</h6>

<!-- If AA2 does not exist -->
<h4>AA1 BBB</h4>
<h6>BBB</h6>

Here are my current templates

<!-- This template works fine and dandy -->
<xsl:template match="AAA">
    <h4>
    <xsl:copy-of select="AAA1"/>
    <xsl:choose>
    <xsl:when test="AAA2"/>
        <xsl:copy-of select="AAA2"/>
    </xsl:when>
    <xsl:otherwise>
        <xsl:for-each select="child::BBB">
            <xsl:if test="position() = 1">
                <xsl:copy-of select="BBB"/>
            </xsl:if>
        </xsl:for-each>
     </xsl:otherwise>
     </xsl:choose>
     <h4>
     <xsl:apply-templates/>
</xsl:template>

<!-- This is where I get confused -->
<xsl:template match="BBB">
        <h6>
	<xsl:choose>
        <!-- If there is an AAA2 we always put down BBB -->
	<xsl:when test="parent::AAA/AAA2">
		<xsl:copy-of select="BBB"/>
	</xsl:when>
        
       <!-- This doesn't work but it should skip the first BBB and
grab the rest -->
	<xsl:when test="not(count(preceding-sibling::*[name()=name(current())])+1)
= 1">
		<p class="sub">(<xsl:copy-of select="subsectionnumber"/>)&#160;
		<xsl:copy-of select="subsectiontext"/></p>
	</xsl:when>
	</xsl:choose>
       </h6>
	<xsl:apply-templates/>
</xsl:template>

Ok, I think that about covers it, thanks for any help or advice you can offer

Spencer

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