Subject: Re: [xsl] (newby) define an attribute based on an attribute value From: Mukul Gandhi <mukul_gandhi@xxxxxxxxx> Date: Thu, 31 Mar 2005 23:59:06 -0800 (PST) |
Hi Livio, I think this syntax will be required.. <xsl:value-of select="A[@id='123']/B/@v"/> You are using [@v] which is evaluation to a boolean The expression: A[@id='123']/B[@v] is selecting B nodes(which *have* v attribute) , which are child of A nodes(whose id attribute has value 123). And <xsl:value-of select="A[@id='123']/B[@v]"/> will return the concatenated string value of such nodes. Regards, Mukul --- dalloro@xxxxxxxxx wrote: > Hi, > > I'm a newby in XSL tranformations. I need to > trasform an XML file into > another XML file with a different structure. > > Inside a template I build an element named Point > that has several > attributes. The value of one of these attributes > depends on the value > of an attribute in the source XML (the attribute v > of the element B > that I filtered through the parent 'id', in the code > below) > > [snip] > <xsl:element name="Point"> > [snip] > <xsl:attribute name="PointAttribute"> > <xsl:value-of select="A[@id='123']/B[@v]"/> > </xsl:attribute> > [snip] > </xsl:element> > [snip] > > I would like to obtain a 'Point' element with an > attribute called > 'PointAttribute' with the same value of the 'v' > attribute of the > element 'B'. > > What is the best way to deal with this problem? > > I thank you for the help. > Best regards. > > Livio. > > __________________________________ Do you Yahoo!? Yahoo! Personals - Better first dates. More second dates. http://personals.yahoo.com
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