Subject: Re: [xsl] problem using last() within <xsl:for-each-group> From: David Carlisle <davidc@xxxxxxxxx> Date: Fri, 1 Apr 2005 11:52:08 +0100 |
<xsl:variable name="endline" select="'
x;'"/> that's not well formed XML, your stylesheet should not have parsed (spurious x in a hex number) <xsl:value-of select="concat('The current node is ', current())"/> current() is like . here you are using it in value-of so you get the string value of teh selected node, but as these are empty elements you get the empty string. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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