Subject: Re: [xsl] Select nodes with equal position From: Midsummer Sun <midsummer.sun@xxxxxxxxx> Date: Sun, 3 Apr 2005 09:32:47 +0530 |
Thank you David. This also works - <xsl:value-of select="../../colspec[count(current()/preceding-sibling::entry)+1]/@colname"/> (got idea from your answer) Seems more programmer friendly to me(not a XPath expert like you) Best regards, On Apr 3, 2005 2:49 AM, David Carlisle <davidc@xxxxxxxxx> wrote: > > Why this should not work - > <xsl:template match="entry"> > <xsl:value-of select="../../colspec[position()]/@colname"/> > </xsl:template> > > colspec[2] means colspec[position()=2] and so selects the second colspec > > colspec[position()] means colspec[position()=position()] which is the > same as colspec as the predicate is always true. > > David > > ________________________________________________________________________ > This e-mail has been scanned for all viruses by Star. The > service is powered by MessageLabs. For more information on a proactive > anti-virus service working around the clock, around the globe, visit: > http://www.star.net.uk > ________________________________________________________________________
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