Subject: Re: [xsl] How to find the deepest node? From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 7 Apr 2005 17:07:28 +0100 |
This is a grouping problem (where you only want one group) <xsl:key name="t" select="title" use="count(ancestor::*)"/> ... <xsl:for-each select="//title"> <xsl:sort data-type="number" select="count(ancestor::*)"> <xsl:if test="position()=last()"> <xsl:apply-templates select="key('t',count(ancestor::*))"/> </xsl:if> </xsl:for-each> David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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