Subject: Re: [xsl] XSL-FO & Images From: "craig webber" <craigwebber@xxxxxxxxxxx> Date: Mon, 18 Apr 2005 16:25:35 +0000 |
<xsl:template match="image"> <fo:block> <img> <xsl:attribute name="src"> <xsl:value-of select="."/> </xsl:attribute> </img> </fo:block> </xsl:template>
<xsl:template match="image"> <fo:block> <fo:external-graphic src="url(test.jpg)"/> </fo:block> </xsl:template>
From: David Carlisle <davidc@xxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] XSL-FO & Images Date: Mon, 18 Apr 2005 17:13:38 +0100
yes of course, XSLT doesn't know anything about FO (or any other XML format in the result tree) Your question is very general, just asking is it possible to find all elements of some sort in an input tree and generate an output element for each one. That in essence is just exactly what XSLT does, so it's hard to know where to give specific advice unless you can narrow down your problem.
<xsl:template match="/"> <fo:table> <xsl:apply-templates select="//image"/> </fo:table> </xsl:template>
<xsl:template match="image"> <fo:table-row> <fo:table-cell <fo:external-graphic src="url({.})/> </fo:table-cell </fo:table-row> </xsl:template>
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