RE: [xsl] Best approach

["Michael Kay" <mike@xxxxxxxxxxxx>]

There's been a lot of discussion on comparing documents on this list a
couple of weeks ago.

Here's one approach: use the XPath 2.0 expression

    deep-equal(doc('result1.xml'), doc('result2.xml'))

If that doesn't meet your needs, you'll have to explain your needs.

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: RahilQ [mailto:qamar_rahil@xxxxxxxxxxx] 
> Sent: 21 April 2005 19:25
> To: XSL List
> Subject: [xsl] Best approach
> 
> Hi
> 
> Im sure theres a fairly straight-forward and obvious approach 
> available. 
> So Id like some suggestions.
> 
> I have written loads of .xsl files for transforming some .xml 
> files. The 
> result is a set of 2 separate .xml files (output from 2 separate .xsl 
> files) on which Id like to carry out some comparisons.
> 
> Graphically for example the process is such:
> 
> Step 1 :   Model1.xml -->  Transf1.xsl --> Result1.xml
> 
> Step 2:    Model2.xml -->  Transf2.xsl --> Result2.xml
> 
> 
> My main problem isnt how to compare Result1 and Result2 but 
> how to start 
> writing them. In which kind of file?
> 
> - Can I import these two files into one .xsl and work upon them? 
> or
> - Should I and can I write some <?xml-stylesheet 
> href='Compare.xsl'.....?> in Result1.xml when generating it from 
> Transf1.xsl ? Then only import Result2.xml in Compare.xsl ?
> 
> Could someone please advise me on the best approach. I need a 
> solution 
> that can be as piped as possible as all this will ultimately 
> form part 
> of one button on the GUI.
> 
> Thanks
> Rahil