Re: [xsl] working with multiple files

[RahilQ <qamar_rahil@xxxxxxxxxxx>]

Hi

Michael Kay wrote:

> There's been a lot of discussion on comparing documents on this list a
> couple of weeks ago.
>
> Here's one approach: use the XPath 2.0 expression
>
>    deep-equal(doc('result1.xml'), doc('result2.xml'))
>
> If that doesn't meet your needs, you'll have to explain your needs.
>  

deep-equal() wont be a solution in my case as I dont have two versions 
of the same .xml with minor differences.

Instead what I have is two .xml files which contain information on the 
same topic albeit in a different style. I have done some XSLT to make 
their structures look similar though.

So if I carry forward the recipe example that was discussed in an 
earlier thread, then I have two different chefs writing out the recipe 
for a particular dish. In such a case, there will be a lot of 
similarities between the two recipes but there will be some differences 
as well because the two chefs havent been communicating with each other 
earlier. Also the position at which common information is contained in 
the two recipes may differ i.e. its there but not at the same structural 
level !

I have to therefore use one .xml file as the source and then hunt 
through the entire second .xml file to see if the information exists in 
it as well. In addition, I also have to highlight features that are not 
present in the source xml but there in the second xml. Ive tried to make 
my search easier by having similar xml structures for the two files.

Sorry for such a verbose explanation but didnt know a better way to 
explain my requirement.

Thanks
Rahil