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Subject: Re: [xsl] Print number of chars depending upon int value From: "Ranjan K. Baisak" <ranjanbaisak@xxxxxxxxx> Date: Fri, 22 Apr 2005 03:56:04 -0700 (PDT) |
>select="substring('...................................',
> 1, $myLength)"/> should do the trick!
But if $myLength is greater than the number of chars
in the string?
-Ranjan
--- Eric van der Vlist <vdv@xxxxxxxxxxxx> wrote:
> On ven, 2005-04-22 at 03:47 -0700, Ranjan K. Baisak
> wrote:
> > In a reporting application, I need to print number
> of
> > chars e.g. '.'s depending upon some numeric
> variable.
> > SO it would be a kind of array of chars.
>
> Isn't a string a kind of array of chars ;-) ???
>
> > Any function available for the same?
>
> what about substring()?
>
>
http://www.w3.org/TR/1999/REC-xpath-19991116#function-substring
>
> <xsl:value-of
>
select="substring('...................................',
> 1, $myLength)"/> should do the trick!
>
> Eric
>
> --
> Curious about Relax NG? Read my book online.
>
> http://books.xmlschemata.org/relaxng/
>
------------------------------------------------------------------------
> Eric van der Vlist http://xmlfr.org
> http://dyomedea.com
> (ISO) RELAX NG ISBN:0-596-00421-4
> http://oreilly.com/catalog/relax
> (W3C) XML Schema ISBN:0-596-00252-1
> http://oreilly.com/catalog/xmlschema
>
------------------------------------------------------------------------
>
>
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