Re: [xsl] Print number of chars depending upon int value

["Ranjan K. Baisak" <ranjanbaisak@xxxxxxxxx>]

:D David, I am quite agree with you.
This is an instance where I have mentioned keeping eye
with other functions/constructs available in XSLT2.0
I really did not count how many exact lines would be
there :(

-Ranjan
--- David Carlisle <davidc@xxxxxxxxx> wrote:
> 
> > Should not there be an alternative for any
> function in
> > xslt2.0 in xslt 1.0. 
> 
> No, of course not.
> What would be the difference between (xslt1 + xslt1
> versions of all
> xslt2 features) and xslt2.
> 
> This is not specific to xslt, for any language, if a
> new feature is
> added in a new version, it's not available in the
> old one.
> 
> > Otherwise it is required to write 100 lines of
> code as
> > mentioned by Eliot Harold.
> 
> 
> In this case it's not 100's of lines. Unless your
> padding needs to be
> really long (ie nore characters than there are nodes
> in your stylesheet)
> then you can do
> 
> <xsl:for-each
> select="(document('')//node())[position() &lt;=
> $count]">.</xsl:for-each>
> 
> if you want to do a fully general recursive loop
> then something like
> 
> <xsl:template name="x">
>  <xsl:param name="n"/>
>   <xsl:if test="$n!=0">.<xsl:call-template name="x">
>      <xsl:with-param name="n" select="$n - 1"/>
>      </xsl:call-template>
>   </xsl:if>
> </xsl:template>
> 
> which is 7 lines, 3 of which are just closing open
> elements so it's
> really only 3 lines of code.
> 
> David
> 
>
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