Subject: Re: [xsl] accessing different nodes when comparing two xml files From: RahilQ <qamar_rahil@xxxxxxxxxxx> Date: Mon, 25 Apr 2005 15:37:45 +0100 |
Thanks Rahil
I have declared two variables that will contain the two document trees.
<xsl:variable name="first">First.xml</xsl:variable> <xsl:variable name="second" select="document('Second.xml')/Top"/>
That $first does not contain a document it contains a result tree fragment that corresponds to a document node that has (just) a text node with value the string "First.xml".
presulamably you intended that to be <xsl:variable name="first" select="document('First.xml')/Top"/>
<xsl:for-each select="$first/f Thus will give you a compile time error as $first is a result tree fragment not a node set.
However your xpaths are not going to work I expect.
for example
$second/following-sibling::SubConcepts
If Second.xml is a well formed XML file it has only one top level element, presumably called Top. $second is bound to that element node and so will have no following siblings, so this will be th eempty set.
David
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