Re: [xsl] First attempt at xsl:result-document

Subject: Re: [xsl] First attempt at xsl:result-document
From: Spencer Tickner <spencertickner@xxxxxxxxx>
Date: Mon, 25 Apr 2005 13:53:10 -0700
Excellent,

Thank you Michael, it looks like that's exactly what I'm looking for.
Thanks for the time and adivice. I'll post back if I have any problems
but that looks straight forward enough.

Thanks again,

Spencer

On 4/25/05, Michael Kay <mike@xxxxxxxxxxxx> wrote:
> Before you start rendering this data, you should group it hierarchically so
> that clauses are nested within sections and sections are nested within
> parts. You can do this conveniently using group-starting-with:
>
> <xsl:template match="act">
> <xsl:for-each-group select="*" group-starting-with="part">
> <part>
>   <xsl:for-each-group select="current-group()[not(self::part)]"
> group-starting-with="section">
>     <section>
>       <xsl:copy-of select="current-group()[not(self::section)]"/>
>     </section>
>   </xsl:for-each-group>
> </part>
> </xsl:for-each-group>
> </xsl:template>
>
> Michael Kay
> http://www.saxonica.com/
>
> > -----Original Message-----
> > From: Spencer Tickner [mailto:spencertickner@xxxxxxxxx]
> > Sent: 25 April 2005 21:39
> > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> > Subject: Re: [xsl] First attempt at xsl:result-document
> >
> > Hi Michael, thank you very much for the reply.
> >
> > I had a feeling this was the case before, thank you for re-affirming
> > my supicions. So do you have any advice for pulling this information
> > out? or is it impossible? I appreciate any thoughts you have on this
> > matter (unless they have to do with re-writing my entire xml base :)).
> >
> > Thank you
> >
> > Spencer
> >
> > On 4/25/05, Michael Kay <mike@xxxxxxxxxxxx> wrote:
> > > > Thanks once again for the reply. I've retested my
> > application and do
> > > > not think the URI is the problem. As an example
> > > >
> > > > .
> > > > .
> > > > .
> > > > <xsl:for-each select="part">
> > > > <xsl:variable name="filename" select="concat('file:///',
> > > > position(), '.htm'"/>
> > > > <xsl:result-document href={$filename}" format="html">
> > > > <html>
> > > > <body>
> > > >
> > > > <!-- Test -->
> > > > <xsl:value-of="/act/title"/>
> > > > <!--End of Test -->
> > > >
> > > > <xsl:apply-templates mode="content"/>
> > > > </body>
> > > > </html>
> > > > </xsl:result-document>
> > > > </xsl:for-each>
> > > > </xsl:template>
> > > >
> > > > Now let's say I have 4 parts in an xml document. I do get
> > 5 files in
> > > > the end (1 table of contents and 4 parts) and each file
> > is named as
> > > > expected and each file picks up the title. However none
> > of the files
> > > > pick up any content from the <xsl:apply-templates
> > mode="content"/>.
> > > >
> > >
> > > Your example XML was:
> > >
> > > <act>
> > > > > <part>this is a part we will divide a file on</part>
> > > > > <section>This is a section</section>
> > > > > <clause>This is a clause</clause>
> > > > > <part>This is another part, in the new scheme of
> > things, a second
> > > > > file</part>
> > > > > <section>Yet another section</section>
> > > > > </act>
> > >
> > > In this example, the only child of the <part> element is a
> > single text node.
> > > I would expect this text to be output as a result of the
> > > <xsl:apply-templates mode="content"/> call. I would not
> > expect the section
> > > and clause elements to be output, because they are not
> > children of the
> > > <part>.
> > >
> > > Michael Kay
> > > http://www.saxonica.com/

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