RE: [xsl] Splitting multiple node occurrences into separate xmls

["Michael Kay" <mike@xxxxxxxxxxxx>]

> I need to do a transformation that will take an input xml 
> string in a format 
> that is something like
> ...<a>1</a><a>2</a><a>3</a><a>4</a>...
> and apart from transforming it, will split the multiple node 
> occurrences for 
> "a" into different xml's i.e.
> xml[1]=<a>1</a>
> xml[2]=<a>2</a>...

XSLT 2.0 solution:

<xsl:template match="a">
  <xsl:result-document href="file{position()}.xml">
    <xsl:copy-of select="."/>
  </xsl:result-document>
</xsl:template>

Some XSLT 1.0 processors have extensions that do similar things.

Michael Kay
http://www.saxonica.com/



> 
> I was thnking that if xsl offers some kind of looping 
> facility, that may 
> help. But then xsl transformation presumably being single-input, 
> single-output process, just an xsl maynot by itself suffice. 
> Is there a 
> possibility that somehow I can have a java loop pass a 
> looping variable into 
> the xsl-sheet, so that the first transformation gives me the first 
> occurrence of "a", and so on.
> 
> Another approach could be to let the xsl transformation 
> return a single xml 
> that has the multiple "a" occurrences and then subsequently 
> seperate them 
> out by carrying out XPath/DOM operations on the transformed xml.
> 
> 
> - Vishwajit.