Subject: [xsl] Newbie question on Recusrion using XLST 1.0 Part 2 From: "Marco Mastrocinque" <mmfive@xxxxxxxxxxxxxxx> Date: Mon, 2 May 2005 13:07:33 +1000 |
Hi Aron, I have multiple <division> elements, which are grouped by the <employees> element, which has multiple <employee> elements. All the <division> are unique (I took care of this using the unique, and key and keyref tags in an xml schema, which is not shown.) Sorry I'm new to XPATH and XSLT 1.0. Thanks Marco Mastrocinque. -----Original Message----- From: Aron Bock [mailto:aronbock@xxxxxxxxxxx] Sent: Monday, 2 May 2005 11:57 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: [xsl] Newbie question on Recusrion using XLST 1.0 Part 2 Marco, either I've not understood the complexity of what you're attempting, or you've unwittingly made it more comples than necessary. If you don't have multiple <division> elements with the same @DID, the following is all you need: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="text"/> <xsl:template match="/"> <xsl:for-each select="company/division"> <xsl:sort select="@DID"/> <xsl:value-of select="@DID"/> <xsl:text>
</xsl:text> <xsl:for-each select="employees/employee"> <xsl:sort select="ENAME"/> <xsl:value-of select="concat(' ', @EID, ', ', ENAME, ', ', OFFICE)"/> <xsl:text>
</xsl:text> </xsl:for-each> </xsl:for-each> </xsl:template> </xsl:stylesheet> For suggestions on handling more sophisticated grouping please see www.jenitennison.com Regards, --A From: "Marco Mastrocinque" <mmfive@xxxxxxxxxxxxxxx> <company> <division DID="Sal"> <employees> <employee EID="EMP001"> <ENAME>Joe Blow</ENAME> <OFFICE>1.2.27</OFFICE> <BIRTHDATE>1963-08-01</BIRTHDATE> <SALARY>28790</SALARY> </employee> <employee EID="EMP002"> <ENAME>John Doe</ENAME> <OFFICE>1.2.2</OFFICE> <BIRTHDATE>1970-08-01</BIRTHDATE> <SALARY>29855</SALARY> </employee> </employees> </division> <division DID="SOF"> <employees> <employee EID="EMM001"> <ENAME>Mark Smith</ENAME> <OFFICE>1.2.27</OFFICE> <BIRTHDATE>1966-08-01</BIRTHDATE> <SALARY>35000</SALARY> </employee> <employee EID="EMM002"> <ENAME>John Doe</ENAME> <OFFICE>1.2.2</OFFICE> <BIRTHDATE>1977-08-01</BIRTHDATE> <SALARY>40000</SALARY> </employee> </employees> </division> </company> I'm having using a recursive routine (see below) to display the following elements and attributes: 1) The employee EID attribute such as 'EMP001', followed by 2) The element text of ENAME, such as 'Joe Blow', 3) The element text of OFFICE, such as '1.2.27' 4) The output must be formatted such that the employees of each division are grouped together. _________________________________________________________________ Don't just search. Find. Check out the new MSN Search! http://search.msn.click-url.com/go/onm00200636ave/direct/01/
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