Subject: Re: [xsl] <xsl:sort> From: George Cristian Bina <george@xxxxxxx> Date: Sat, 07 May 2005 11:12:51 +0300 |
<xsl:template match="document"> <xsl:for-each select="child::node()"> <!-- whatever processing you want to do --> </xsl:for-each> <xsl:apply-templates select="product"> <xsl:sort select="category" data-type="number" order="descending"/> </xsl:apply-templates> </xsl:template>
Best Regards, George --------------------------------------------------------------------- George Cristian Bina <oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger http://www.oxygenxml.com
Hi, folks.
I have an XML document which structure is the following:
<document> <header> <paragraph> <subheader> <paragraph> . . . <product> <partname> <category> . . . </product> <product> <partname> <category> . . . </product> . . . </document>
In a template that matches on "document", I have the following:
<xsl:template match="document"> <xsl:for-each select="child::node()"> // etc... </xsl:for-each> </xsl:template>
The XSLT stylesheet works fine, but now I need to sort the "product" elements based upon the "category" element and in descending order. The category content is numeric.
How would I execute this from within the "document" template?
Here's what I've tried.
<xsl:template match="document"> <xsl:for-each select="child::node()"> <xsl:if test="product"> <xsl:apply-templates select="."> <xsl:sort select="category" data-type="number" order="descending" /> </xsl:apply-templates> </xsl:if> </xsl:for-each> </xsl:template>
Where am I going wrong? Thanks for your feedback.
Respectfully,
ASP
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