Re: [xsl] For-each loop or recursion

[Oleg Konovalov <olegkon@xxxxxxxxx>]

How do I get a position of last occurrence of min ?

Do I have to use recursion?
Can I scan using for-each from the end of the sequence
to the beginning ?

Please advise,
Oleg.


On 5/16/05, Oleg Konovalov <olegkon@xxxxxxxxx> wrote:
> > > I need to compare current and next values of the node var2 [and var3]
> > > and find the first occurrence when var2[position()] = var2[next, i.e.
> > > position()+1]
> > > Are you saying that is impossible to do in XSLT ?
> >
> > It's almost certainly possible to do what you want but your decription
> > is pretty hard to follow. You need to describe the transformation that
> > you want to do not just use bits of XPath and hope that we understand
> > what you want.  Xpath's position() function for example does not relate
> > to the position of a node within a tree (a node can have any number of
> > values returned buy position(), depending on how the node is
> > selected). I'm _guessing_ that what you want to know is the sibling order
> > of the node in the input tree in which case you might want
> > following-sibling::*[1] but that is just a guess.
>
> OK, lets try to get a position of the first occurrence when var2 = max
node.
> As I said, I don't want to change the order of the nodes in a tree with
sort.
> What would be a correct syntax ?
>
> <xsl:for-each select=mystruct/myarray1[1]/myvar>
>   <xsl:if var2=*[last()]>
>     <xsl:value-of select="position()">
>   </xsl:if>
> </xsl:for-each>
>
> The goal is to trim the table [see my previous post],
> get rid of multiple identical occurrences of rebate1 & rebate2.
>
> Do you understand me ?
>
> Thank you,
> Oleg.
>
>
> >
> >   I want from inside for-each loop mystruct/myarray1[i]/myvar
> >   [or does it require recursion?]
> >   compare the values is the parallel branch,
> >   of parallel "current" node ../../myarray2[i]/myvar/var3 and its "next
node".
> >   Again, where:
> >   mystruct/myarray1[i]/myvar/var2 and
> >   mystruct/myarray2[i]/myvar/var3
> >
> > Again you are just typing in syntactically correct XPath and asking "can
> > I do that" since the Xpath you typed above is syntactically correct then
> > clearly you can do that, but I have no idea if that will do what you
> > want, as you've not said what you are trying to do. For example do your
> > elements with name myarray1 have child elements with name i ? If they do
> > not, then the above XPath's will select nothing.
> >
> > > Is there an easy way to find out the max value of the node (child
elements)
> > > without sorting it ?
> > > The sequence of nodes I am dealing with is supposed to be in increasing
order,
> >
> > If you know it's already sorted, just take the last
> > select="*[last()]"
> > or in your case take the last of each then you only have two itemsto
> > compare which you can do with &gt; to work out the overall maximum.
> >
> >
> > David
> >
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