RE: [xsl] Finding min and max

["Andreas Schnabl" <Oandie@xxxxxxx>]

Hi there,

I already read the the way how to find the min and max node of an element.
The difference for my stylesheet is that my element consists of two values.
I would need the smallest value of the number with the leading 35. So it has
to be something with substring-before(.,' ') as I tried below, to get the
first part of the element.   

The values look like this:
<gml>3569875,45 5896534,23/>gml>
<gml>3552365,56 583256975,56/>gml>

I tried the version with the recursive template, but it didn't work out.
My code looks like that:

<xsl:template name="minimum_x">
  <xsl:param name="nodes" />
  <xsl:param name="min_temp" select="0"/>
     <xsl:choose>
	<xsl:when test="$nodes" >
	 <xsl:variable name="min-so-far">
	   <xsl:call-template name="minimum_x">
	     <xsl:with-param name="nodes" select="$nodes[position() != 1]" />
	     <xsl:with-param name="min_temp" select="substring-before($nodes[1],'
')"/>
	  </xsl:call-template>
	</xsl:variable>
        <xsl:choose>
          <xsl:when test="$min-so-far &lt; .">
            <xsl:value-of select="$min-so-far" />
          </xsl:when>
          <xsl:otherwise>
            <xsl:value-of select="." />
          </xsl:otherwise>
        </xsl:choose>
     </xsl:when>			
  </xsl:choose>
</xsl:template>			

any help will be appreciated


andy

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