RE: [xsl] element to root

["Michael Kay" <mike@xxxxxxxxxxxx>]

Am I right in guessing that your task is to insert a newline before a <br>
element?

If I'm right then you just do

<xsl:template match="*">
  <xsl:copy>
  <xsl:copy-of select="@*"/>
  <xsl:apply-templates/>
  </xsl:copy>
</xsl:template>

<xsl:template match="br">
  <xsl:text>&#xa;</xsl:text>
  <xsl:copy>
  <xsl:copy-of select="@*"/>
  <xsl:apply-templates/>
  </xsl:copy>
</xsl:template>

Michael Kay
http://www.saxonica.com/
    

> -----Original Message-----
> From: jpk [mailto:jopaki@xxxxxxxxx] 
> Sent: 31 May 2005 17:35
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] element to root
> 
> Hi all,
> 
> I am still struggling with coming up with an xsl
> transform that will convert this source:
> 
> ------
> <p>
>   <span style="style a">
>     span a text 1
>     <span style="style b">
>       span b pre br text
>       <br name="b"/>
>       span b post br text
>     </span>
>     span a text 2
>   </span>
> </p>
> ------
> 
> TO:
> 
> ------
> <p>
>   <span style="style a">
>     span a text 1
>     <span style="style b">
>       span b pre br text
> 
>       <br name="b"/>
>       span b post br text
>     </span>
>     span a text 2
>   </span>
> </p>
> ------
> 
> 
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