RE: [xsl] To eliminate duplicate entries

Subject: RE: [xsl] To eliminate duplicate entries
From: <tomas.vanek@xxxxxxxxxxxxx>
Date: Wed, 8 Jun 2005 13:42:06 +0200
If you have to filter out employees with duplicate empId:

<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet version="1.0"
  <xsl:output method="xml" indent="yes" encoding="utf-8"/>

  <xsl:key name="employee" use="empId" match="/*/employee"/>

  <xsl:template match="/">
      <xsl:copy-of select="*/employee[count(.|key('employee', empId)[1]


-----Original Message-----
From: X.P.Pratibha :-) [mailto:xp_pratibha@xxxxxxxxxx]
Sent: Wednesday, June 08, 2005 12:39 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] To eliminate duplicate entries

Hi Mukul,
  Thanks ...
By the by..If my XML data is of the following foramt...

	<employee name="ppp">
	<employee name="xxx"/>
	<employee name="yyy"/>

Now what I have to use in the place @name (I guess this for attribute)
If my empID is of this type ...


Mukul Gandhi wrote:
> Or please try this XSL ..
> <?xml version="1.0"?>
> <xsl:stylesheet
> xmlns:xsl="";
> version="1.0">
>  <xsl:output method="text" />
>  <xsl:template match="/example">
>    <xsl:for-each select="employee[not(@name =
> preceding-sibling::employee/@name)]">
>      <xsl:value-of select="@name"
> /><xsl:text>&#xa;</xsl:text>
>    </xsl:for-each>
>  </xsl:template>
> </xsl:stylesheet>
> Regards,
> Mukul
> --- "X.P.Pratibha :-)" <xp_pratibha@xxxxxxxxxx> wrote:
>>Hi all.,
>>    I am novoice to XSL .
>>My XML has multiple Duplicate entries and while displaying it through
>>XSL I have to eliminate the multiple duplicate entries and display
>>only one entry .
>>Is there is any way to check the uniqueness of the data to be
>>displayed in XSL.
>>In my xml data say if "employee id" is unqui ,Is there anyway to check

>>the replication of employee id in xsl.
>>Any links or sample code will be of great help.
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