RE: [xsl] Copy all nodes

["Ranjan K. Baisak" <ranjanbaisak@xxxxxxxxx>]

Would it be like
<xsl:template match="/">
<xsl:apply-templates/>	
</xsl:template>
<xsl:template match="@*|node()">
    <xsl:apply-templates select="@*|node()" />
</xsl:template>
<xsl:template match="connectivity[not(*)]">
 	<xsl:copy>
    	<xsl:apply-templates select="@*|node()" />
	</xsl:copy>
</xsl:template>

regards,
Ranjan

--- Michael Kay <mike@xxxxxxxxxxxx> wrote:

> Your template is copying a node only if it has one
> or more children named
> Entry.
> 
> Use a standard identity template and supplement it
> with the second rule:
> 
> <xsl:template match="Entry[not(*)]"/>
> 
> Michael Kay
> http://www.saxonica.com/ 
> 
> > -----Original Message-----
> > From: Ranjan K. Baisak
> [mailto:ranjanbaisak@xxxxxxxxx] 
> > Sent: 15 June 2005 07:39
> > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> > Subject: Re: [xsl] Copy all nodes 
> > 
> > I forgot to mention, if any <Entry> element with
> zero
> > child, then I dont wan to copy.
> > 
> > <xsl:template match="@*|node()">
> >   <xsl:copy>
> >   	<xsl:if test="count(child::Entry)>0">
> >     	<xsl:apply-templates select="@*|node()" />
> > 	</xsl:if>
> >   </xsl:copy>
> > </xsl:template>
> > 
> > The above template does not work
> > 
> > -Ranjan
> > 
> > --- "Ranjan K. Baisak" <ranjanbaisak@xxxxxxxxx>
> wrote:
> > 
> > > Hello,
> > >      I need a xpath expression to copy all nodes
> > > from
> > > source.
> > > e.g. input: <Entry>
> > > 		<Session>2004/5</Session>
> > > 		<Department>Accounting and
> Finance</Department>
> > > 	</Entry>
> > > 
> > > output:<Entry>
> > > 		<Session>2004/5</Session>
> > > 		<Department>Accounting and
> Finance</Department>
> > > 	</Entry>
> > > Can anybody tell me the xpath expression for the
> > > same.
> > > 
> > > regards,
> > > Ranjan
> > > 
> > >
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