Subject: AW: [xsl] only display if subnodes occur more than once From: "Prerovsky, Clemens" <Clemens.Prerovsky@xxxxxxx> Date: Thu, 23 Jun 2005 15:08:37 +0200 |
Anrew Welch wrote: > <xsl:template match="sub_a|sub_b|sub_c"> > <xsl:variable name="copy" > select="boolean(*/following-sibling::*[local-name() = > preceding-sibling::*/local-name()])"/> > > <xsl:if test="$copy"> > <xsl:copy-of select="."/> > </xsl:if> > </xsl:template> <xsl:if test="boolean(*/following-sibling::*[local-name() = preceding-sibling::*/local-name()])"> works fine for my needs - thank you very much! Could'nt have done it without you! Best regards, Clemens Prerovsky
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
AW: [xsl] only display if subnodes , Prerovsky, Clemens | Thread | RE: [xsl] only display if subnodes , Michael Kay |
Re: [xsl] xsl:element in XSLT 1.0, Jack Matheson | Date | Re: [xsl] Linking to a 6 level tag , Aron Bock |
Month |