Re: [xsl] xsl transform

[David Carlisle <davidc@xxxxxxxxx>]

Your input format looks a lot nicer than your output format:-)

<xsl:template match="/results"> (this works fine)
	<root>
		<xsl:attribute name="fields">
			<xsl:for-each select="row[1]/*">
				<xsl:value-of select="local-name()"/>
				<xsl:if test="not(position()=last())">|</xsl:if>
			</xsl:for-each>
		</xsl:attribute>
 <e>
			<xsl:for-each select="row[1]/*">
		  <xsl:attribute name="a{position()}"/>
                       <xsl:value-of select="."/>
			</xsl:for-each>
</e>
	</root>
</xsl:template>

would produce
<e a1="p1" a2="p2"

etc

If you really need attribute names a b c ..

then 

easiest is to have a file
names.xml that looks like
<x>
<a/>
<b/>
...
<aa/>
..
<az/>
</x>


Then replace

		  <xsl:attribute name="a{position()}"/>


by
		  <xsl:variable name="p" select="a{position()}"/>
		  <xsl:attribute name="{name(document('names.xml')/x/*[$p])}"/>

David

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