Subject: Re: [xsl] test if null From: Ragulf Pickaxe <ragulf.pickaxe@xxxxxxxxx> Date: Wed, 29 Jun 2005 02:42:18 +0200 |
Hi Jay, The solution that David Carlisle gave you first works. If you did not get it to work, you should rather ask yourself (or the list) why it didn't work for you. What we where discussing was not checking whether <sample> element was present but whether it had a text() child. That is, the scope was within the <sample> element. In this scope, using DC's solution is the most efficient way of solving your problem. In short: <xsl:if test="*">....</xsl:if> does not distinguish between <sample/> and <sample>some text</sample> <xsl:if test="string-length(.)=0">....</xsl:if> does not distinguish between <sample/> and <sample><sub/></sample> <xsl:if test="node()">....</xsl:if> does distinguish between <sample/> and all variations of <sample>....</sample> I hope that you can see the difference. Regards, Ragulf Pickaxe :-) On 6/28/05, -= jay =- <deepsweech@xxxxxxxxx> wrote: > Hi Ragulf, > The node is always present, but im checking if it returns empty string or not > like: > <sample /> -->this is empty > <sample>not empty</sample> ->not empty > > thanks guys!
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