Subject: [xsl] Problems grouping adjacent siblings From: "Huditsch Roman" <Roman.Huditsch@xxxxxxxxxxxxx> Date: Thu, 30 Jun 2005 08:37:54 +0200 |
Good morning list, I would like to group adjacent siblings which share the same local-name into a container element. Given this structure <ax> <e></e> <r></r> <exp>Example</exp> <exp>bla bla</exp> <exp>jada jada</exp> <b></b> <e></e> <exp>Example 2</exp> <exp>bla bla</exp> <v></v> </ax> <bx> <c></c> <exp>Example 3</exp> <exp>bla bla</exp> <b></b> </bx> The following output should be produced: <ax> <e></e> <r></r> <remark> <exp>Example</exp> <exp>bla bla</exp> <exp>jada jada</exp> </remark> <b></b> <e></e> <remark> <exp>Example 2</exp> <exp>bla bla</exp> </remark> <v></v> </ax> <bx> <c></c> <r></r> <remark> <exp>Example 3</exp> <exp>bla bla</exp> </remark> <b></b> </bx> I thought that this would be the classical use-case for an <xsl:for-each-group> with @group-adjacent, but I am getting the strangest results... I don't even know if it is better to do the grouping in a template matching exp[not(preceding-sibling::*[1][local-name()='exp']) or in a template matching exp's parent I also tried to find a @group-starting-with solution, since the first <exp> always starts with the string 'Example'. But with no success either.... Can you help me with this problem? Thank you very much for your help! Wbr, Roman
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