Subject: Re: [xsl] only display if subnodes occur more than once From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 5 Jul 2005 23:24:06 +0100 |
> Note that David and I construed this differently: he, that only the element > children with siblings the same name should be output; I, that all the > children of the element containing such children should be output. oh well, variation number 3... at least it's getting shorter <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:key name="x" match="root/*/*" use="concat(generate-id(..),':',name())"/> <xsl:template match="root"> <root> <xsl:copy-of select="*/*[generate-id()=generate-id(key('x',concat(generate-id(..),':',name()))[2])]/.."/> </root> </xsl:template> </xsl:stylesheet> David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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