Re: [xsl] only display if subnodes occur more than once

Subject: Re: [xsl] only display if subnodes occur more than once
From: David Carlisle <davidc@xxxxxxxxx>
Date: Tue, 5 Jul 2005 23:24:06 +0100
> Note that David and I construed this differently: he, that only the element 
> children with siblings the same name should be output; I, that all the 
> children of the element containing such children should be output.

oh well, variation number 3...

at least it's getting shorter

<xsl:stylesheet
   version="1.0"
   xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>
<xsl:key name="x" match="root/*/*" use="concat(generate-id(..),':',name())"/>
<xsl:template match="root">
<root>
<xsl:copy-of
select="*/*[generate-id()=generate-id(key('x',concat(generate-id(..),':',name()))[2])]/.."/>
</root>
</xsl:template>
</xsl:stylesheet>

David

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