[xsl] Sorting Problem

Subject: [xsl] Sorting Problem
From: "Dhami, Ankit \(UMR Student\)" <atdhfb@xxxxxxx>
Date: Thu, 7 Jul 2005 09:13:09 -0500
Hi guys,

Here is the XML file:

<all>
<log_entry run_time="4084" action="retrieveUserPreferencesBean"
username="Matt"/>
<log_entry run_time="4085" action="filterBean" username="Jason"/>
<log_entry run_time="4086" action="retrieveUserPreferencesBean"
username="Joe"/>
<log_entry run_time="4087" action="retrieveUserPreferencesBean"
username="Joe"/>
</all>


Here is the sorting part of XSL file:

<xsl:for-each-group select="//log_entry" group-by="@action">
<xsl:sort select="count(current-group()/@action)" order="ascending"/>
<xsl:for-each-group select="current-group()" group-by="@username">
<tr>
<td><xsl:value-of select="./@username"/></td>
<td><xsl:value-of select="./@action"/></td>
<td><xsl:value-of select="count(current-group()/@action)"/></td>
</tr>
</xsl:for-each-group>
</xsl:for-each-group>


The output HTML is:

<tr>
<td>Matt</td>
<td>retrieveUserPreferencesBean</td>
<td>1</td> ..........( count field)
</tr>
<tr>
<td>Joe</td>
<td>retrieveUserPreferencesBean</td>
<td>2</td>..........( count field)
</tr>
<tr>
<td>Jason</td>
<td>filterBean</td>
<td>1</td>..........( count field)
</tr>

which is not as expected since it did not sort it based on count.


Here, I am trying to sort the "count" column based on value obtained by
function count().

Any replies appreciated.

Thanks,

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