Re: [xsl] Concatenating the attribute values of ancestors

[Mukul Gandhi <mukul_gandhi@xxxxxxxxx>]

Hi David,
  I mistakenly misspelled the parameter name. Inspite
of correcting it, I am still getting the same error.
You posted the correct solution. Thanks about it..

Regards,
Mukul

--- David Carlisle <davidc@xxxxxxxxx> wrote:

> 
> you should get an error about using an undefined
> param
>             <xsl:with-param name="anestors"
>                                     ^
> 
> 
> However you don't need all that recursion it looks
> like a single Xpath
> 
> <xsl:stylesheet
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>                 version="2.0">
> 
> 
> <xsl:template match="*">
>   <xsl:copy>
>    <xsl:copy-of select="@*"/>
>     <xsl:attribute name="newseq"
>      select="string-join(ancestor-or-self::*/(if
> (@seq) then string(@seq) else '0'),'')"/>
>     <xsl:apply-templates/>
>    </xsl:copy>
> </xsl:template>     
> 
> </xsl:stylesheet>
> 
>
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